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- sq5 = sqrt 5 :: Double8 KB (1,150 words) - 15:41, 5 July 2022
- where (ai, af) = properFraction . sqrt $ 1 + 24 * (fromInteger n)12 KB (1,626 words) - 05:45, 9 March 2021
- (truncate $ sqrt $ fromIntegral x)^2 == x21 KB (3,012 words) - 03:07, 8 December 2011
- * square / sqrt / distance? - also supported (less well), again I haven't done anything.10 KB (1,671 words) - 03:59, 16 August 2014
- test = V.foldl (\ a b -> a * sqrt (fromIntegral b)) 023 KB (3,342 words) - 19:28, 25 April 2013
- slow way of doing a '''sqrt'''. (a2 + 1 / sqrt k)25 KB (3,873 words) - 11:08, 6 March 2023
- ratio = toRational (2/(1+sqrt(5)::Double))19 KB (2,315 words) - 15:36, 4 December 2012
- Prelude> sqrt 215 KB (2,246 words) - 23:44, 15 May 2012
- z = ceiling $ sqrt $ fromIntegral a + 1 -- p2>=z => p2*p2>a (h,ps) = span (<= (floor.sqrt $ fromIntegral m+1)) ops58 KB (8,594 words) - 20:34, 6 May 2023
- Prelude> sqrt 213 KB (1,986 words) - 17:59, 9 August 2019
- ...e (2*a)] là où delta = b*b - delta de la base 4*a*c = du sqrt exp, notation, sqrt34 KB (5,567 words) - 09:54, 7 April 2008
- let last = pI $ floor $ sqrt (fromIntegral n)15 KB (2,018 words) - 01:29, 26 April 2021
- Prelude> sqrt 214 KB (2,164 words) - 16:35, 9 October 2016
- let gr = (1+(sqrt 5))/2 -- golden ratio, 1.618033988749895 sqrt (offset.x^2 + offset.y^2 + offset.z^2) < r40 KB (6,787 words) - 01:19, 8 April 2014
- distXYZ (x1, y1, z1) (x2, y2, z2) = sqrt (xd * xd + yd * yd + zd * zd) ...in the class 'Floating', which of course includes 'Double'. The type of 'sqrt' can be found here:111 KB (19,450 words) - 17:55, 23 October 2019