Difference between revisions of "User talk:PaoloMartini"

Revision as of 22:28, 14 September 2006

$\sum _{i=0}^{n}a_{i}\sum _{j=0}^{i}{n \choose k}x^{n-j}(-1)^{j}$

$\sum _{i=0}^{n}{n \choose k}x^{n-i}(-1)^{i}\sum _{j=i}^{n}a_{j}$

Revision as of 19:36, 14 September 2006 (view source) PaoloMartini (talk \| contribs) ← Older edit	Revision as of 22:28, 14 September 2006 (view source) PaoloMartini (talk \| contribs) Newer edit →
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	+	<math>\sum_{i=0}^n a_i \sum_{j=0}^i {n \choose k} x^{n-j} (-1)^j</math>
	+
	+	<math>\sum_{i=0}^n {n \choose k} x^{n-i} (-1)^i \sum_{j=i}^n a_j </math>