Haskell Quiz/FizzBuzz/Solution Ninju: Difference between revisions
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Latest revision as of 15:19, 6 February 2021
I think this is probably what I'd do in the interview situation - i.e. the first and most obvious thing that comes to mind.
module Main where
main :: IO ()
main = printAll $ map fizzBuzz [1..100]
where
printAll [] = return ()
printAll (x:xs) = putStrLn x >> printAll xs
fizzBuzz :: Integer -> String
fizzBuzz n | n `mod` 15 == 0 = "FizzBuzz"
| n `mod` 5 == 0 = "Fizz"
| n `mod` 3 == 0 = "Buzz"
| otherwise = show n