99 questions/Solutions/16: Difference between revisions
< 99 questions | Solutions
(a slight variation using guards) |
(Added a new (complicated, maybe ugly) solution. This was my first approach, but after getting to know take and drop, I came up with the same solution as the 3rd one. I thought I may post it anyway) |
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<haskell> | <haskell> | ||
dropEvery n = map snd . filter ((n/=) . fst) . zip (cycle [1..n]) | dropEvery n = map snd . filter ((n/=) . fst) . zip (cycle [1..n]) | ||
</haskell> | |||
A more complicated approach which first divides the input list into sublists that do not contain the nth element, and then concatenates the sublists to a result list (if not apparent: the author's a novice): | |||
<haskell> | |||
dropEvery :: [a] -> Int -> [a] | |||
dropEvery [] _ = [] | |||
dropEvery xs n = concat (split n xs) | |||
where | |||
split _ [] = [] | |||
split n xs = fst splitted : split n ((safetail . snd) splitted) | |||
where | |||
splitted = splitAt (n-1) xs | |||
safetail xs | null xs = [] | |||
| otherwise = tail xs | |||
</haskell> | </haskell> |
Revision as of 05:43, 18 August 2010
(**) Drop every N'th element from a list.
dropEvery :: [a] -> Int -> [a]
dropEvery [] _ = []
dropEvery (x:xs) n = dropEvery' (x:xs) n 1 where
dropEvery' (x:xs) n i = (if (n `divides` i) then
[] else
[x])
++ (dropEvery' xs n (i+1))
dropEvery' [] _ _ = []
divides x y = y `mod` x == 0
An alternative iterative solution:
dropEvery :: [a] -> Int -> [a]
dropEvery list count = helper list count count
where helper [] _ _ = []
helper (x:xs) count 1 = helper xs count count
helper (x:xs) count n = x : (helper xs count (n - 1))
Yet another iterative solution which divides lists using Prelude:
dropEvery :: [a] -> Int -> [a]
dropEvery [] _ = []
dropEvery list count = (take (count-1) list) ++ dropEvery (drop count list) count
A similar approach using guards:
dropEvery :: [a] -> Int -> [a]
dropEvery xs n
| length xs < n = xs
| otherwise = take (n-1) xs ++ dropEvery (drop n xs) n
Using zip:
dropEvery n = map snd . filter ((n/=) . fst) . zip (cycle [1..n])
A more complicated approach which first divides the input list into sublists that do not contain the nth element, and then concatenates the sublists to a result list (if not apparent: the author's a novice):
dropEvery :: [a] -> Int -> [a]
dropEvery [] _ = []
dropEvery xs n = concat (split n xs)
where
split _ [] = []
split n xs = fst splitted : split n ((safetail . snd) splitted)
where
splitted = splitAt (n-1) xs
safetail xs | null xs = []
| otherwise = tail xs