Closure: Difference between revisions

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<hask>f</hask> returns a closure, because the variable <hask>x</hask>, which is bound outside of the [[lambda abstraction]] is used inside its definition.  
<hask>f</hask> returns a closure, because the variable <hask>x</hask>, which is bound outside of the [[lambda abstraction]] is used inside its definition.  


An interesting a side note: the context in which <hask>x</hask> was bound shouldn't even exist anymore, and wouldn't, had the lambda abstraction not closed around x.
An interesting side note: the context in which <hask>x</hask> was bound shouldn't even exist anymore, and wouldn't, had the lambda abstraction not closed around x.


[[Category:Glossary]]
[[Category:Glossary]]

Revision as of 18:06, 29 September 2010

A closure, the opposite of a combinator, is a function that makes use of free variables in its definition. It 'closes' around some portion of its environment. for example

f x = (\y -> x + y)

f returns a closure, because the variable x, which is bound outside of the lambda abstraction is used inside its definition.

An interesting side note: the context in which x was bound shouldn't even exist anymore, and wouldn't, had the lambda abstraction not closed around x.