(*) Split a list into two parts; the length of the first part is given.
Do not use any predefined predicates.
Solution using take and drop:
split xs n = (take n xs, drop n xs)
Alternatively, we have the following recursive solution:
split :: [a] -> Int -> ([a], [a]) split  _ = (, ) split l@(x : xs) n | n > 0 = (x : ys, zs) | otherwise = (, l) where (ys,zs) = split xs (n - 1)
The same solution as above written more cleanly:
Note that this function, with the parameters in the other order, exists as
split :: [a] -> Int -> ([a], [a]) split xs 0 = (, xs) split (x:xs) n = let (f,l) = split xs (n-1) in (x : f, l)