(Some additional solutions for this question)
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Revision as of 06:22, 2 April 2014
(**) Flatten a nested list structure.
data NestedList a = Elem a | List [NestedList a] flatten :: NestedList a -> [a] flatten (Elem x) = [x] flatten (List x) = concatMap flatten x
or without concatMap
flatten :: NestedList a -> [a] flatten (Elem a ) = [a] flatten (List (x:xs)) = flatten x ++ flatten (List xs) flatten (List ) = 
flatten2 :: NestedList a -> [a] flatten2 a = flt' a  where flt' (Elem x) xs = x:xs flt' (List (x:ls)) xs = flt' x (flt' (List ls) xs) flt' (List ) xs = xs
or with foldr
flatten3 :: NestedList a -> [a] flatten3 (Elem x ) = [x] flatten3 (List xs) = foldr (++)  $ map flatten3 xs
or with an accumulator function:
flatten4 = reverse . rec  where rec acc (List ) = acc rec acc (Elem x) = x:acc rec acc (List (x:xs)) = rec (rec acc x) (List xs)
We have to define a new data type, because lists in Haskell are homogeneous. [1, [2, [3, 4], 5]] is a type error. Therefore, we must have a way of representing a list that may (or may not) be nested.
Our NestedList datatype is either a single element of some type (Elem a), or a list of NestedLists of the same type. (List [NestedList a]).