Difference between revisions of "Euler problems/11 to 20"

From HaskellWiki
Jump to navigation Jump to search
(Added solution for problem 14)
m
Line 42: Line 42:
 
where n' = if even n then n `div` 2 else (3*n)+1
 
where n' = if even n then n `div` 2 else (3*n)+1
   
problem_14 = fst $ head $ qsort [(x, length $ p14s x) | x <- [1 .. 999999]]
+
problem_14 = fst $ head $ sortBy (\(_,x) (_,y) -> compare y x) [(x, length $ p14s x) | x <- [1 .. 999999]]
  +
where qsort [] = []
 
qsort (x:xs) = qsort left ++ [x] ++ qsort right
 
where left = filter ((>(snd x)) . snd) xs
 
right = filter ((<=(snd x)) . snd) xs
 
 
</haskell>
 
</haskell>
   

Revision as of 14:40, 2 July 2007

Problem 11

What is the greatest product of four numbers on the same straight line in the 20 by 20 grid?

Solution:

problem_11 = undefined

Problem 12

What is the first triangle number to have over five-hundred divisors?

Solution:

problem_12 = head $ filter ((> 500) . nDivisors) triangleNumbers
    where triangleNumbers = scanl1 (+) [1..]
          nDivisors n     = product $ map ((+1) . length) (group (primeFactors n))
          primes          = 2 : filter ((== 1) . length . primeFactors) [3,5..]
          primeFactors n  = factor n primes
              where factor n (p:ps) | p*p > n        = [n]
                                    | n `mod` p == 0 = p : factor (n `div` p) (p:ps)
                                    | otherwise      = factor n ps

Problem 13

Find the first ten digits of the sum of one-hundred 50-digit numbers.

Solution:

nums = ... -- put the numbers in a list
problem_13 = take 10 . show . sum $ nums

Problem 14

Find the longest sequence using a starting number under one million.

Solution:

p14s :: Integer -> [Integer]
p14s n = n : p14s' n
  where p14s' n = if n' == 1 then [1] else n' : p14s' n'
          where n' = if even n then n `div` 2 else (3*n)+1

problem_14 = fst $ head $ sortBy (\(_,x) (_,y) -> compare y x) [(x, length $ p14s x) | x <- [1 .. 999999]]

Problem 15

Starting in the top left corner in a 20 by 20 grid, how many routes are there to the bottom right corner?

Solution:

problem_15 = undefined

Problem 16

What is the sum of the digits of the number 21000?

Solution:

dsum 0 = 0
dsum n = let ( d, m ) = n `divMod` 10 in m + ( dsum d )

problem_16 = dsum ( 2^1000 )

Problem 17

How many letters would be needed to write all the numbers in words from 1 to 1000?

Solution:

-- not a very concise or beautiful solution, but food for improvements :)

names = concat $
  [zip  [(0, n) | n <- [0..19]]
        ["", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight"
        ,"Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen"
        ,"Sixteen", "Seventeen", "Eighteen", "Nineteen"]
  ,zip  [(1, n) | n <- [0..9]]
        ["", "Ten", "Twenty", "Thirty", "Fourty", "Fifty", "Sixty", "Seventy"
        ,"Eighty", "Ninety"]
  ,[((2,0), "")]
  ,[((2, n), look (0,n) ++ " Hundred and") | n <- [1..9]]
  ,[((3,0), "")]
  ,[((3, n), look (0,n) ++ " Thousand") | n <- [1..9]]]

look n = fromJust . lookup n $ names

spell n = unwords $ if last s == "and" then init s else s
  where
    s     = words . unwords $ map look digs'
    digs  = reverse . zip [0..] . reverse . map digitToInt . show $ n
    digs' = case lookup 1 digs of
                Just 1  ->
                  let [ten,one] = filter (\(a,_) -> a<=1) digs in
                      (digs \\ [ten,one]) ++ [(0,(snd ten)*10+(snd one))]
                otherwise -> digs

problem_17 xs = sum . map (length . filter (`notElem` " -") . spell) $ xs

Problem 18

Find the maximum sum travelling from the top of the triangle to the base.

Solution:

problem_18 = undefined

Problem 19

How many Sundays fell on the first of the month during the twentieth century?

Solution:

problem_19 = undefined

Problem 20

Find the sum of digits in 100!

Solution:

problem_20 = let fac n = product [1..n] in
             foldr ((+) . Data.Char.digitToInt) 0 $ show $ fac 100

Alternate solution, summing digits directly, which is faster than the show, digitToInt route.

dsum 0 = 0
dsum n = let ( d, m ) = n `divMod` 10 in m + ( dsum d )

problem_20' = dsum . product $ [ 1 .. 100 ]