# Euler problems/91 to 100

### From HaskellWiki

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properDivisorsSum = accumArray (+) 1 (0,1000000) | properDivisorsSum = accumArray (+) 1 (0,1000000) | ||

$ (0,-1):[(k,factor)| | $ (0,-1):[(k,factor)| | ||

− | + | factor<-[2..1000000 `div` 2] | |

− | + | , k<-[2*factor,2*factor+factor..1000000] | |

− | + | ] | |

base = S.fromList [1..1000000] | base = S.fromList [1..1000000] | ||

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s' = foldl' (flip S.delete) s explored | s' = foldl' (flip S.delete) s explored | ||

</haskell> | </haskell> | ||

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== [http://projecteuler.net/index.php?section=view&id=96 Problem 96] == | == [http://projecteuler.net/index.php?section=view&id=96 Problem 96] == |

## Revision as of 15:08, 30 August 2007

## Contents |

## 1 Problem 91

Find the number of right angle triangles in the quadrant.

Solution:

problem_91 = undefined

## 2 Problem 92

Investigating a square digits number chain with a surprising property.

Solution:

problem_92 = undefined

## 3 Problem 93

Using four distinct digits and the rules of arithmetic, find the longest sequence of target numbers.

Solution:

problem_93 = undefined

## 4 Problem 94

Investigating almost equilateral triangles with integral sides and area.

Solution:

problem_94 = undefined

## 5 Problem 95

Find the smallest member of the longest amicable chain with no element exceeding one million.

Solution which avoid visiting a number more than one time :

import Data.Array.Unboxed import qualified Data.IntSet as S import Data.List takeUntil _ [] = [] takeUntil pred (x:xs) = x : if pred x then takeUntil pred xs else [] chain n s = lgo [n] $ properDivisorsSum ! n where lgo xs x | x > 1000000 || S.notMember x s = (xs,[]) | x `elem` xs = (xs,x : takeUntil (/= x) xs) | otherwise = lgo (x:xs) $ properDivisorsSum ! x properDivisorsSum :: UArray Int Int properDivisorsSum = accumArray (+) 1 (0,1000000) $ (0,-1):[(k,factor)| factor<-[2..1000000 `div` 2] , k<-[2*factor,2*factor+factor..1000000] ] base = S.fromList [1..1000000] problem_95 = fst $ until (S.null . snd) f ((0,0),base) where f (p@(n,m), s) = (p', s') where setMin = head $ S.toAscList s (explored, chn) = chain setMin s len = length chn p' = if len > m then (minimum chn, len) else p s' = foldl' (flip S.delete) s explored

## 6 Problem 96

Devise an algorithm for solving Su Doku puzzles.

Solution:

problem_96 = undefined

## 7 Problem 97

Find the last ten digits of the non-Mersenne prime: 28433 × 2^{7830457} + 1.

Solution:

problem_97 = (28433 * 2^7830457 + 1) `mod` (10^10)

## 8 Problem 98

Investigating words, and their anagrams, which can represent square numbers.

Solution:

problem_98 = undefined

## 9 Problem 99

Which base/exponent pair in the file has the greatest numerical value?

Solution:

problem_99 = undefined

## 10 Problem 100

Finding the number of blue discs for which there is 50% chance of taking two blue.

Solution:

problem_100 = undefined