Declaration vs. expression style
(Redirected from Expression style)
There are two main styles of writing functional programs, which are both supported by Haskell mainly because several language designers preferred these different styles.
In the declaration style you formulate an algorithm in terms of several equations that shall be satisfied.
In the expression style you compose big expressions from small expressions.
Comparison[edit]
As illustration for the two styles, Simon Peyton Jones give two implementations of the Prelude function filter
:
filter :: (a -> Bool) -> [a] -> [a]
Declaration style[edit]
filter p [] = []
filter p (x:xs)
| p x = x : rest
| otherwise = rest
where
rest = filter p xs
Expression style[edit]
filter =
\p -> \ xs ->
case xs of
[] -> []
(x:xs) ->
let rest = filter p xs
in if p x
then x : rest
else rest
Syntactic elements[edit]
There are characteristic elements of both styles.
Declaration style | Expression-style | ||
---|---|---|---|
where clause
|
let expression
| ||
Function arguments on left hand side: | f x = x*x |
Lambda abstraction: | f = \x -> x*x
|
Pattern matching in function definitions: | f [] = 0 |
case expression: |
f xs = case xs of [] -> 0
|
Guards on function definitions: | f [x] | x>0 = 'a' |
if expression: |
f [x] = if x>0 then 'a' else ...
|
See also[edit]
- Let vs. Where
- History of Haskell (in section 4.4)