# Haskell Quiz/Grid Folding/Solution Dolio

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< Haskell Quiz | Grid Folding(Difference between revisions)

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− | [[Category: | + | [[Category:Haskell Quiz solutions|Grid Folding]] |

The basis for my solution is simple. Consider each square to be a single-element list initially. Then, a row of such squares is a list of such lists. An entire grid is then a list of those lists. | The basis for my solution is simple. Consider each square to be a single-element list initially. Then, a row of such squares is a list of such lists. An entire grid is then a list of those lists. | ||

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hzipper = zipWith (++) . (map reverse . reverse) | hzipper = zipWith (++) . (map reverse . reverse) | ||

− | folder z = uncurry z . ap (flip splitAt) ( | + | folder z = uncurry z . ap (flip splitAt) ((`div` 2) . length) |

− | pretty = unlines . map unwords . | + | pretty = unlines . map (unwords . map show) |

− | output s | + | output s | all isSpace s = error "Invalid folding scheme" |

− | + | | otherwise = putStr s | |

− | + | ||

main = do [n, s] <- getArgs | main = do [n, s] <- getArgs | ||

output . pretty . foldl (flip fold) (grid $ read n) $ s | output . pretty . foldl (flip fold) (grid $ read n) $ s | ||

</haskell> | </haskell> |

## Latest revision as of 11:14, 12 February 2010

The basis for my solution is simple. Consider each square to be a single-element list initially. Then, a row of such squares is a list of such lists. An entire grid is then a list of those lists.

When folding horizontally, one splits each row, reverses the half to go on top (as well as its elements, since they'll be flipped), and zips the two halves together by appending corresponding elements. This results in a top-first list of the stacked squares.

When folding vertically, one splits the grid in half, reverses the half to go on top, and zips the two grid halves together. The function that combines corresponding rows is yet another zip that appends corresponding elements (again, reversing the ones on top).

module Main where import Control.Monad.Reader import Data.Char import System grid n = break . map return $ [1..(n*n)] where break [] = [] break l = let (h,t) = splitAt n l in h : break t fold 'T' = folder vzipper fold 'B' = folder (flip vzipper) fold 'L' = map (folder hzipper) fold 'R' = map (folder $ flip hzipper) fold _ = error "Unrecognized letter." vzipper = zipWith (zipWith $ (++) . reverse) . reverse hzipper = zipWith (++) . (map reverse . reverse) folder z = uncurry z . ap (flip splitAt) ((`div` 2) . length) pretty = unlines . map (unwords . map show) output s | all isSpace s = error "Invalid folding scheme" | otherwise = putStr s main = do [n, s] <- getArgs output . pretty . foldl (flip fold) (grid $ read n) $ s