(Take string/packed string problem from haskell-cafe@ as example)
Revision as of 15:11, 19 March 2006
|Haskell Performance Resource|
Sometimes the cost of representing strings as lists of Char can be too much. In this case, you can instead use packed strings. There are a number of options:
- The standard Data.PackedString type
- One of the newer packed string libraries, for example FastPackedString
- Unboxed arrays of Word8 or Char
- Ptrs to foreign malloced Word8 buffers
The packed string libraries have the benefit over arrays of Word8 or Char types, in that they provide the usual list-like operations.
Pete Chown asked the question:
I want to read a text file. As an example, let's use /usr/share/dict/words and try to print out the last line of the file.
The python version completes in around 0.05s.
2.1 Attempt 1 : [Char]
import System.IO main = readFile "/usr/share/dict/words" >>= putStrLn.last.lines
Run in hugs, this program took several seconds to complete. Problem: interpreted (solution, use a Haskell compiler). Compiled, the program completes in a fairly quick 0.2s. Still, we can do better.
2.2 Attempt 2 : Packed Strings
Using fast, packed strings, we get:
import qualified Data.FastPackedString as P import IO main = P.readFile "/usr/share/dict/words" >>= P.hPut stdout . last . P.lines
Runs in 0.063s
2.3 Attempt 3 : No Lists
Avoid splitting the file into lists at all, and just keep a single buffer (as a C programmer would perhaps do):
import qualified Data.FastPackedString as P import IO main = do P.readFile "/usr/share/dict/words" >>= P.hPut stdout . snd . P.spanEnd (/='\n') . P.init putChar '\n'
Runs in 0.013s