Difference between revisions of "No import of Prelude"
Wlangstroth (talk | contribs) m (→Question) |
(→Answer: Added newer -X version of command line switch) |
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{-# LANGUAGE NoImplicitPrelude #-} |
{-# LANGUAGE NoImplicitPrelude #-} |
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</haskell> |
</haskell> |
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− | to the top of the module, or equivalently compile with <code>-fno-implicit-prelude</code> option. |
+ | to the top of the module, or equivalently compile with <code>-XNoImplicitPrelude</code> (or older <code>-fno-implicit-prelude</code>) option. |
<hask>import Prelude()</hask> is less aggressive than <code>NoImplicitPrelude</code>. |
<hask>import Prelude()</hask> is less aggressive than <code>NoImplicitPrelude</code>. |
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There are some such for which even <code>-fno-implicit-prelude</code> isn't enough; |
There are some such for which even <code>-fno-implicit-prelude</code> isn't enough; |
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I think these are documented in the "bugs" section of the GHC manual. |
I think these are documented in the "bugs" section of the GHC manual. |
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== See also == |
== See also == |
Latest revision as of 15:26, 15 November 2011
Question
Is it possible to not load the Prelude when compiling a Haskell module?
Answer
You can either do
import Prelude()
or add
{-# LANGUAGE NoImplicitPrelude #-}
to the top of the module, or equivalently compile with -XNoImplicitPrelude
(or older -fno-implicit-prelude
) option.
import Prelude()
is less aggressive than NoImplicitPrelude
.
E.g. with the first method some functions are imported which are silently inserted for several syntactic constructs.
A bare untyped integral number is rewritten as fromIntegral num
(so its type will be Num a => a
),
and list generation syntax is rewritten as follows:
[n..]
enumFrom
,
[n..m]
enumFromTo
,
[n,o..]
enumFromThen
,
[n,o..m]
enumFromThenTo
.
There are some such for which even -fno-implicit-prelude
isn't enough;
I think these are documented in the "bugs" section of the GHC manual.
See also
- Haskell-Cafe: Not to load Prelude