Recursion in a monad: Difference between revisions

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People sometimes wonder how to effectively do recursion when inside a
monadic <hask>do</hask>-block. Here's some quick examples:


The problem is to read 'n' lines from stdin, recursively:
The obvious, recursive way:
<haskell>
main = f 3
f 0 = return []
f n = do v  <- getLine
        vs <- f (n-1)
        return $! v : vs
</haskell>
Runs:
<haskell>
    $ runhaskell A.hs
    1
    2
    3
    ["1","2","3"]
</haskell>
Or make it [[tail recursion|tail recursive]]:
<haskell>
f 0 acc = return (reverse acc)
f n acc = do
    v  <- getLine
    f (n-1) (v : acc)
</haskell>
Or abstract the recursion pattern into a fold:
<haskell>
f n = do
    s <- foldM fn [] [1..n]
    return (reverse s)
  where fn acc _ = do x <- getLine
                      return (x:acc)
</haskell>
And finally, apply some functor and pointfree shortcuts:
<haskell>
f n = reverse `fmap` foldM fn [] [1..n]
    where fn acc _ = (: acc) `fmap` getLine
</haskell>
[[Category:Code]]
[[Category:Glossary]]

Latest revision as of 15:18, 6 February 2021

People sometimes wonder how to effectively do recursion when inside a monadic do-block. Here's some quick examples:

The problem is to read 'n' lines from stdin, recursively:

The obvious, recursive way:

main = f 3

f 0 = return []
f n = do v  <- getLine
         vs <- f (n-1)
         return $! v : vs

Runs:

    $ runhaskell A.hs
    1
    2
    3
    ["1","2","3"]

Or make it tail recursive:

f 0 acc = return (reverse acc)
f n acc = do
    v  <- getLine
    f (n-1) (v : acc)

Or abstract the recursion pattern into a fold:

f n = do
    s <- foldM fn [] [1..n]
    return (reverse s)

  where fn acc _ = do x <- getLine
                      return (x:acc)

And finally, apply some functor and pointfree shortcuts:

f n = reverse `fmap` foldM fn [] [1..n]
    where fn acc _ = (: acc) `fmap` getLine