# Difference between revisions of "99 questions/Solutions/15"

From HaskellWiki

< 99 questions | Solutions

(added solution using list monad) |
(Added an alternative and more verbose solution) |
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repli :: [a] -> Int -> [a] |
repli :: [a] -> Int -> [a] |
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repli xs n = xs >>= replicate n |
repli xs n = xs >>= replicate n |
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+ | </haskell> |
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+ | |||

+ | or, a more verbose solution without the use of <hask>replicate</hask>: |
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+ | <haskell> |
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+ | repli :: [a] -> Int -> [a] |
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+ | repli xs n = foldl (\acc e -> acc ++ repli' e n) [] xs |
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+ | where |
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+ | repli' _ 0 = [] |
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+ | repli' x n = x : repli' x (n-1) |
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</haskell> |
</haskell> |

## Revision as of 05:11, 10 August 2011

(**) Replicate the elements of a list a given number of times.

```
repli :: [a] -> Int -> [a]
repli xs n = concatMap (replicate n) xs
```

or, in Pointfree style:

```
repli = flip $ concatMap . replicate
```

alternatively, without using the `replicate`

function:

```
repli :: [a] -> Int -> [a]
repli xs n = concatMap (take n . repeat) xs
```

or, using the list monad:

```
repli :: [a] -> Int -> [a]
repli xs n = xs >>= replicate n
```

or, a more verbose solution without the use of `replicate`

:

```
repli :: [a] -> Int -> [a]
repli xs n = foldl (\acc e -> acc ++ repli' e n) [] xs
where
repli' _ 0 = []
repli' x n = x : repli' x (n-1)
```