# 99 questions/Solutions/4

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(correction (foldl) and shortened version of foldr) |
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## Revision as of 22:46, 1 December 2010

(*) Find the number of elements of a list.

myLength :: [a] -> Int myLength [] = 0 myLength (_:xs) = 1 + myLength xs

myLength' = foldl (\n _ -> n + 1) 0 myLength'' = foldr (\_ n -> n + 1) 0 myLength''' = foldr (\_ -> (+1)) 0

`myLength' xs = snd $ last $ zip xs [1..] -- Just for fun`

length

Prelude