(**) Define predicates and/2, or/2, nand/2, nor/2, xor/2, impl/2 and equ/2 (for logical equivalence) which succeed or fail according to the result of their respective operations; e.g. and(A,B) will succeed, if and only if both A and B succeed.
A logical expression in two variables can then be written as in the following example: and(or(A,B),nand(A,B)).
Now, write a predicate table/3 which prints the truth table of a given logical expression in two variables.
The first step in this problem is to define the Boolean predicates:
-- NOT negates a single Boolean argument not' :: Bool -> Bool not' True = False not' False = True -- Type signature for remaining logic functions and',or',nor',nand',xor',impl',equ' :: Bool -> Bool -> Bool -- AND is True if both a and b are True and' True True = True and' _ _ = False -- OR is True if a or b or both are True or' False False = False or' _ _ = True -- NOR is the negation of 'or' nor' a b = not' $ or' a b -- NAND is the negation of 'and' nand' a b = not' $ and' a b -- XOR is True if either a or b is True, but not if both are True xor' True False = True xor' False True = True xor' _ _ = False -- IMPL is True if a implies b, equivalent to (not a) or (b) impl' a b = (not' a) `or'` b -- EQU is True if a and b are equal equ' True True = True equ' False False = True equ' _ _ = False
The above implementations build each logic function from scratch; they could be shortened using Haskell's builtin equivalents:
and' a b = a && b or' a b = a || b nand' a b = not (and' a b) nor' a b = not (or' a b) xor' a b = and' (or' a b) (nand' a b) impl' a b = or' (not a) b equ' a b = a == b
Some could be reduced even further using Pointfree style:
and' = (&&) or' = (||) equ' = (==)
The only remaining task is to generate the truth table; most of the complexity here comes from the string conversion and IO. The approach used here accepts a Boolean function (Bool -> Bool -> Bool), then calls that function with all four combinations of two Boolean values, and converts the resulting values into a list of space-separated strings. Finally, the strings are printed out by mapping
putStrLn across the list of strings:
table :: (Bool -> Bool -> Bool) -> IO () table f = mapM_ putStrLn [show a ++ " " ++ show b ++ " " ++ show (f a b) | a <- [True, False], b <- [True, False]]
The table function in Lisp supposedly uses Lisp's symbol handling to substitute variables on the fly in the expression. I chose passing a binary function instead because parsing an expression would be more verbose in haskell than it is in Lisp. Template Haskell could also be used :)