(Just wanted to post a solution using a fold.)
Revision as of 04:53, 28 February 2011
(*) Find out whether a list is a palindrome. A palindrome can be read forward or backward; e.g. (x a m a x).
isPalindrome :: (Eq a) => [a] -> Bool isPalindrome xs = xs == (reverse xs)
isPalindrome'  = True isPalindrome' [_] = True isPalindrome' xs = (head xs) == (last xs) && (isPalindrome' $ init $ tail xs)
Here's one to show it done in a fold just for the fun of it. Do note that it is less efficient then the previous 2 though.
isPalindrome'' :: (Eq a) => [a] -> Bool isPalindrome'' xs = foldl (\acc (a,b) -> if a == b then acc else False) True input where input = zip xs (reverse xs)