Compose

(Difference between revisions)

Compose
is a nice little module which shows off some of the features of the various monads around. The task is to write a function
compose :: [(a -> a)] -> (a -> a)
, which should take a list of functions and chain them together: a value would be fed into the first, which then produces a new value, which is fed into the third, and so on. I.e.
compose [(*2), (+1)] 3 = 8
.

This page illustrates the solution in different monads. Most are a bit of a joke; you'd probably only ever use the first solution presented, but nevertheless the nice features of the various monads are demonstrated.

1 The Sane Solution

```compose :: [(a -> a)] -> a -> a
compose fs v = foldl (flip (.)) id fs \$ v```
This one's easy. We fold over the list using composition as our combinator to join items. We flip it, though, because we want a value to be fed into the first function in the list first, but
f . g
applies
g
before
f
. We use
id
as the starting value, as
id
is an identity for composition.

2 Using State

```composeState :: [(a -> a)] -> a -> a
composeState = execState . mapM modify```
Here we use but a single feature of the very powerful
State
monad. To understand how this code works, consider it in the less eta-reduced form:
`composeState fs v = execState (mapM modify fs) v`
mapM
iterates over the list of functions, applying
modify
to each one. If we were to expand a list after it had been mapped over in this way,
```fs = mapM modify [(*2), (+1), \n -> (n - 5) * 4]
-- fs is entirely equivalent to the following do-block:
fs' = do modify (*2)
modify (+1)
modify (\n -> (n - 5) * 4)```

In other words, we obtain a stateful computation that modifies the state with the first function in the list, then the second, and so on.

```composeReader :: [(a -> a)] -> a -> a
compose' (f:fs) = local f (compose' fs)```
The
State
, but not as general. It doesn't allow you to permanently change the environment, so that spoils our previous approach of chaining
modify
calls together in a do-block. However, there is a useful little function
local
which allows us to temporarily modify the environment for a given computation. We can use this to recurse on our list: we modify the environment by the first function in the list for the computation
compose' fs
, which is the recursion on the rest of the list. Again, we could expand out:
```fs = compose' [(*2), (+1), \n -> (n - 5) * 4]
-- again, this is entirely equivalent to the following:
fs' = local (*2) \$
local (+1) \$
local (\n -> (n - 5) * 4) ask```
is a simple function that just returns the current environment. Our tactic in words here is to create a computation (the result of the
compose'
call) which modifies the environment for another computation which further modifies the environment for another computation which modifies the environment yet further... until finally we hit the end of our list and we just return the environment, which has had all the functions in our list applied to it.

Once this composition has been built up, we run it, starting off with an environment of the starting value.

4 Using Writer

```composeWriter :: [(a -> a)] -> a -> a
composeWriter fs v = (execWriter \$ compose' fs) v
where compose' []     = return id
compose' (f:fs) = censor (. f) (compose' fs)```
This example comes with a disclaimer. You should never use
Writer
in this way. This example was really just an experimentation to see if
Writer
could be twisted in this way! Our tactic here is really rather similar to that of the
example. We build up a computation which is the result of modifying the environment (or, actually, as we're working in
Writer
, we modify the output).
censor
Writer
and produces a new
Writer
whose output is the same but whose log entry has been modified by the function.". So, we compose each function in turn onto the "log output" (which is actually a chain of composed functions).

Once this computation has been build up, we extract this long composition chain, and apply it to our starting value.

5 Using Cont

I'm pretty sure this could be done, but I don't have a clue how! If you know
Cont

6 References

Mainly see All About Monads, specifically chapter two, which has overviews and examples for all the major monads.

7 The whole code

In case you wish to run this code, here it is in its entirety:

```-- Thread a value through a list of function applications

module Compose where

compose :: [(a -> a)] -> a -> a
compose fs v = foldl (flip (.)) id fs \$ v

composeState :: [(a -> a)] -> a -> a
composeState = execState . mapM modify

composeReader :: [(a -> a)] -> a -> a
compose' (f:fs) = local f (compose' fs)

composeWriter :: [(a -> a)] -> a -> a
composeWriter fs v = (execWriter \$ compose' fs) v
where compose' []     = return id
compose' (f:fs) = censor (. f) (compose' fs)

main = do let fs = [(+1), (*2), \n -> (n - 5) * 4]
v  = 3
putStrLn \$ "compose: "       ++ (show \$ compose       fs v)
putStrLn \$ "compostState: "  ++ (show \$ composeState  fs v)