Determining the type of an expression

From HaskellWiki

Problem[edit]

How can I find out the type of an expression or a subexpression?


Solution[edit]

Type of expressions[edit]

You can start the interactive environment of Hugs or GHC (GHCi) and use the :type directive:

 Prelude> :type map fromEnum "Text"
 map fromEnum "Text" :: [Int]

If the expression is a top-level binding in a module, you can use the :info directive.

 Prelude> :info map
 map :: (a -> b) -> [a] -> [b]

Using :browse Modulename you can show the types of all top-level variables. This way you can write many functions in a module without a type signature, find them out and add them afterwards. But be warned that due to the Monomorphism restriction the automatically infered signatures are not always the ones you want.

Type of subexpressions[edit]

Say, you have the expression map f "Text" == [1,2,3] and you want to find out of what type the f must be. This is also possible, just type

 Prelude> :type \ f -> map f "Text" == [1,2,3]
 \f -> map f "Text" == [1,2,3] :: Num a => (Char -> a) -> Bool

Here Bool is the type of map f "Text" == [1,2,3] and Num a => (Char -> a) is the type of f.

Now imagine, that the function f cannot be chosen freely, but is an instantiation of a polymorphic function. E.g. of what concrete type is id in map id "Text"?

 Prelude> :type \ f -> map (id `asTypeOf` f) "Text"
 \f -> map (asTypeOf id f) "Text" :: (Char -> Char) -> [Char]

Using Data.Typeable[edit]

Say you'd like to catch a specific exception that is thrown, but you don't know which one it is. In the repl, you can catch SomeException and use Data.Typeable.typeOf on the value inside SomeException:

λ> import Data.Typeable
λ> let catcher (SomeException e) = print (typeOf e)
λ> let failer = openFile "foo" WriteMode >> openFile "foo" WriteMode >> print "opened twice"
λ> catch failer catcher
IOException