Euler problems/21 to 30
Problem 21
Evaluate the sum of all amicable pairs under 10000.
Solution: This is a little slow because of the naive method used to compute the divisors.
problem_21 = sum [m+n | m <- [2..9999], let n = divisorsSum ! m, amicable m n]
where amicable m n = m < n && n < 10000 && divisorsSum ! n == m
divisorsSum = array (1,9999)
[(i, sum (divisors i)) | i <- [1..9999]]
divisors n = [j | j <- [1..n `div` 2], n `mod` j == 0]
An alternative.
problem_21_v2 = sum $ filter amic [1..10000]
where amic n = n /= m && n == sdivs m
where m = sdivs n
sdivs n = sum $ filter (\m -> n `mod` m == 0) [1..n-1]
Here is an alternative using a faster way of computing the sum of divisors.
problem_21_v3 = sum [n | n <- [2..9999], let m = d n,
m > 1, m < 10000, n == d m]
d n = product [(p * product g - 1) `div` (p - 1) |
g <- group $ primeFactors n, let p = head g
] - n
primeFactors = pf primes
where
pf ps@(p:ps') n
| p * p > n = [n]
| r == 0 = p : pf ps q
| otherwise = pf ps' n
where (q, r) = n `divMod` p
primes = 2 : filter (null . tail . primeFactors) [3,5..]
Problem 22
What is the total of all the name scores in the file of first names?
Solution:
import Data.Char
import Data.List
problem_22 =
sum . zipWith (*) [ 1 .. ] . map score
where
score = sum . map ( subtract 64 . ord )
main=do
f<-readFile "names.txt"
let names=sort$tail$("":)$read $"["++f++"]"
print $problem_22 names
Problem 23
Find the sum of all the positive integers which cannot be written as the sum of two abundant numbers.
Solution:
import Data.List
-- An other interesting fact is that every even number not in
-- 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 26, 28, 34, 46 can
-- be expressed as the sum of two abundant numbers.
-- For odd numbers this question is a little bit more tricky.
-- http://www-maths.swan.ac.uk/pgrads/bb/project/node25.html
notEven=[2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 26, 28, 34, 46]
problem_23 = 1 +sum notEven +sum notOdd
abundant :: Integer -> [Integer]
abundant n = [a | a <- [1,3..n], (sum $ factors a) - a > a]
oddAbu=abundant 28123
canExp x =take 1 [(b,y)|b<-oddAbu,let y=x-b,y>1,(sum$factors y)-y>y ]
notOdd=[x|x<-[3,5..28123],canExp x ==[]]
primes :: [Integer]
primes = 2 : filter ((==1) . length . primeFactors) [3,5..]
primeFactors :: Integer -> [Integer]
primeFactors n = factor n primes
where
factor _ [] = []
factor m (p:ps) | p*p > m = [m]
| m `mod` p == 0 = p : factor (m `div` p) (p:ps)
| otherwise = factor m ps
factors :: Integer -> [Integer]
factors = perms . map (tail . scanl (*) 1) . group . primeFactors
where
perms :: (Integral a) => [[a]] -> [a]
perms [] = [1]
perms (x:xs) = perms xs ++ concatMap (\z -> map (*z) $ perms xs) x
Problem 24
What is the millionth lexicographic permutation of the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9?
Solution:
perms [] _= []
perms xs n= do
let m=fac$(length(xs) -1)
let y=div n m
let x = xs!!y
x:( perms ( delete x $ xs ) (mod n m))
problem_24 = perms "0123456789" 999999
Problem 25
What is the first term in the Fibonacci sequence to contain 1000 digits?
Solution:
valid ( i, n ) = length ( show n ) == 1000
problem_25 =
fst . head . filter valid . zip [ 1 .. ] $ fibs
where
fibs = 1 : 1 : 2 : zipWith (+) fibs ( tail fibs )
Problem 26
Find the value of d < 1000 for which 1/d contains the longest recurring cycle.
Solution:
problem_26 =
fst $ maximumBy (\a b -> snd a `compare` snd b)
[(n,recurringCycle n) | n <- [1..999]]
where
recurringCycle d = remainders d 10 []
remainders d 0 rs = 0
remainders d r rs = let r' = r `mod` d
in case findIndex (== r') rs of
Just i -> i + 1
Nothing -> remainders d (10*r') (r':rs)
Problem 27
Find a quadratic formula that produces the maximum number of primes for consecutive values of n.
Solution:
The following is written in literate Haskell:
> import Data.List
To be sure we get the maximum type checking of the compiler,
we switch off the default type
> default ()
Generate a list of primes.
It works by filtering out numbers that are
divisable by a previously found prime
> primes :: [Int]
> primes = sieve (2 : [3, 5..])
> where
> sieve (p:xs) = p : sieve (filter (\x -> x `mod` p > 0) xs)
> isPrime :: Int -> Bool
> isPrime x = x `elem` (takeWhile (<= x) primes)
The lists of values we are going to try for a and b;
b must be a prime, as n² + an + b is equal to b when n = 0
> testRangeA :: [Int]
> testRangeA = [-1000 .. 1000]
> testRangeB :: [Int]
> testRangeB = takeWhile (< 1000) primes
The search
> bestCoefficients :: (Int, Int, Int)
> bestCoefficients =
> maximumBy (\(x, _, _) (y, _, _) -> compare x y) $
> [f a b | a <- testRangeA, b <- testRangeB]
> where
Generate a list of results of the quadratic formula
(only the contiguous primes)
wrap the result in a triple, together with a and b
> f :: Int -> Int -> (Int, Int, Int)
> f a b = ( length $ contiguousPrimes a b
> , a
> , b
> )
> contiguousPrimes :: Int -> Int -> [Int]
> contiguousPrimes a b = takeWhile isPrime (map (quadratic a b) [0..])
The quadratic formula
> quadratic :: Int -> Int -> Int -> Int
> quadratic a b n = n * n + a * n + b
> problem_27 =
> do
> let (l, a, b) = bestCoefficients
>
> putStrLn $ ""
> putStrLn $ "Problem Euler 27"
> putStrLn $ ""
> putStrLn $ "The best quadratic formula found is:"
> putStrLn $ " n * n + " ++ show a ++ " * n + " ++ show b
> putStrLn $ ""
> putStrLn $ "The number of primes is: " ++ (show l)
> putStrLn $ ""
> putStrLn $ "The primes are:"
> print $ take l $ contiguousPrimes a b
> putStrLn $ ""
Problem 28
What is the sum of both diagonals in a 1001 by 1001 spiral?
Solution:
corners :: Int -> (Int, Int, Int, Int)
corners i = (n*n, 1+(n*(2*m)), 2+(n*(2*m-1)), 3+(n*(2*m-2)))
where m = (i-1) `div` 2
n = 2*m+1
sumcorners :: Int -> Int
sumcorners i = a+b+c+d where (a, b, c, d) = corners i
sumdiags :: Int -> Int
sumdiags i | even i = error "not a spiral"
| i == 3 = s + 1
| otherwise = s + sumdiags (i-2)
where s = sumcorners i
problem_28 = sumdiags 1001
You can note that from 1 to 3 there's (+2), and such too for 5, 7 and 9, it then goes up to (+4) 4 times, and so on, adding 2 to the number to add for each level of the spiral. You can so avoid all need for multiplications and just do additions with the following code :
problem_28 = sum . scanl (+) 1 . concatMap (replicate 4) $ [2,4..1000]
Problem 29
How many distinct terms are in the sequence generated by ab for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100?
Solution:
problem_29 = length . group . sort $ [a^b | a <- [2..100], b <- [2..100]]
Problem 30
Find the sum of all the numbers that can be written as the sum of fifth powers of their digits.
Solution:
import Data.Char
limit = snd $ head $ dropWhile (\(a,b) -> a > b)
$ zip (map (9^5*) [1..]) (map (10^) [1..])
fifth n = foldr (\a b -> (toInteger(ord a) - 48)^5 + b) 0 $ show n
problem_30 = sum $ filter (\n -> n == fifth n) [2..limit]