Difference between revisions of "Floyd's cycle-finding algorithm"
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(elements must be unique, e.g. findCycle $ cycle [0,1,0]) |
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− | This is a Haskell |
+ | This is a Haskell implementation of [http://en.wikipedia.org/wiki/Floyd's_cycle-finding_algorithm Floyd's cycle-finding algorithm] for finding cycles in lists. |
<haskell> |
<haskell> |
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findCycle :: Eq a => [a] -> ([a],[a]) |
findCycle :: Eq a => [a] -> ([a],[a]) |
Latest revision as of 00:39, 5 February 2019
This is a Haskell implementation of Floyd's cycle-finding algorithm for finding cycles in lists.
findCycle :: Eq a => [a] -> ([a],[a])
findCycle xxs = fCycle xxs xxs
where fCycle (x:xs) (_:y:ys)
| x == y = fStart xxs xs
| otherwise = fCycle xs ys
fCycle _ _ = (xxs,[]) -- not cyclic
fStart (x:xs) (y:ys)
| x == y = ([], x:fLength x xs)
| otherwise = let (as,bs) = fStart xs ys in (x:as,bs)
fLength x (y:ys)
| x == y = []
| otherwise = y:fLength x ys
This function is essentially the inverse of cycle
. I.e. if xs
and ys
don't have a common suffix, their elements are unique and both are finite, we have that
findCycle (xs ++ cycle ys) == (xs,ys)