Foldl as foldr
When you wonder whether to choose foldl or foldr you may remember,
foldl' can be expressed as
foldr may lean so far right it came back left again.)
The converse is not true, since
foldr may work on infinite lists,
foldl variants never can do.
foldl :: (a -> b -> a) -> a -> [b] -> a foldl f a bs = foldr (\b g x -> g (f x b)) id bs a
Now the question are:
- How can someone find a convolved expression like this?
- How can we benefit from this rewrite?
The answer to the second question is:
We can write a
foldl that may stop before reaching the end of the input list
and thus may also terminate on infinite input.