# Foldl as foldr

From HaskellWiki

When you wonder whether to choose foldl or foldr you may remember,
that both `foldl`

and `foldl'`

can be expressed as `foldr`

.
(`foldr`

may lean so far right it came back left again.)
The converse is not true, since `foldr`

may work on infinite lists,
which `foldl`

variants never can do.
It holds

```
foldl :: (a -> b -> a) -> a -> [b] -> a
foldl f a bs =
foldr (\b g x -> g (f x b)) id bs a
```

Now the question are:

- How can someone find a convolved expression like this?
- How can we benefit from this rewrite?

The answer to the second question is:
We can write a `foldl`

that may stop before reaching the end of the input list
and thus may also terminate on infinite input.