Haskell Quiz/FizzBuzz/Solution Ninju
< Haskell Quiz | FizzBuzz
Jump to navigation
Jump to search
The printable version is no longer supported and may have rendering errors. Please update your browser bookmarks and please use the default browser print function instead.
I think this is probably what I'd do in the interview situation - i.e. the first and most obvious thing that comes to mind.
module Main where
main :: IO ()
main = printAll $ map fizzBuzz [1..100]
where
printAll [] = return ()
printAll (x:xs) = putStrLn x >> printAll xs
fizzBuzz :: Integer -> String
fizzBuzz n | n `mod` 15 == 0 = "FizzBuzz"
| n `mod` 5 == 0 = "Fizz"
| n `mod` 3 == 0 = "Buzz"
| otherwise = show n