# Key-value apply

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BrettGiles (Talk | contribs) (Clean up to make more like a how-to, move context to talk page) |

## Latest revision as of 18:36, 16 February 2007

## [edit] 1 The problem / code

Consider the function:

apply :: (Ord k) => k -> v -> (v -> v) -> [(k,v)] -> [(k,v)] apply k v f ds = let (p1,px) = span ( (k >) . fst) ds (p2,p3) = case px of [] -> ((k,v),[]) (x:xs) -> if fst x == k then ((k, f $ snd x), xs) else ((k, v), x:xs) in p1 ++ (p2 : p3)

This takes a list of key/value pairs and processes it as follows:

- The function is given a key to look for.
- If the key is found, a function is applied to the associated value.
- If the key is
*not*found, it is inserted (at the correct place) with a specified 'default value'.

apply

apply

Ord

However, Haskell already provides this and much more functionality.

## [edit] 2 The solution: Data.Map

When you are making excessive use of (key,value) pairs it is usually time to switch to Data.Map

Data.Map

apply

Data.Map.insertWith

insertWith :: Ord k => (a -> a -> a) -> k -> a -> Map k a -> Map k a

Here the update function receives the new value as well.