Difference between revisions of "State Monad"
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return 'X' :: State Int Char 
return 'X' :: State Int Char 

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get :: State Int Int 
get :: State Int Int 

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put 5 :: State Int () 
put 5 :: State Int () 
Revision as of 06:27, 12 December 2013
The State Monad by Example
This is a short tutorial on the state monad. Emphasis is placed on intuition. The types have been simplified to protect the innocent.
Another longer walkthrough of the state monad can be found in the wiki book section Understanding monads/State.
Contents
Foundations
Primitives
runState (return 'X') 1
('X',1)
return
set the result value but left the state unchanged.
Comments:
return 'X' :: State Int Char runState (return 'X') :: Int > (Char, Int) initial state = 1 :: Int final value = 'X' :: Char final state = 1 :: Int result = ('X', 1) :: (Char, Int)
runState get 1
(1,1)
get
set the result value to the state and left the state unchanged.
Comments:
get :: State Int Int runState get :: Int > (Int, Int) initial state = 1 :: Int final value = 1 :: Int final state = 1 :: Int
runState (put 5) 1
((),5)
put
set the result value to () and set the state value.
Comments:
put 5 :: State Int () runState (put 5) :: Int > ((),Int) initial state = 1 :: Int final value = () :: () final state = 5 :: Int
Combinations
Because (State s) forms a monad, values can be combined together with (>>=) or do{}.
runState (do { put 5; return 'X' }) 1
('X',5)
Comments:
do { put 5; return 'X' } :: State Int Char runState (do { put 5; return 'X' }) :: Int > (Char,Int) initial state = 1 :: Int final value = 'X' :: Char final state = 5 :: Int
postincrement = do { x < get; put (x+1); return x }
runState postincrement 1
(1,2)
predecrement = do { x < get; put (x1); get }
runState predecrement 1
(0,0)
Other Functions
runState (modify (+1)) 1
((),2)
runState (gets (+1)) 1
(2,1)
evalState (gets (+1)) 1
2
execState (gets (+1)) 1
1
Implementation
At its heart, a value of type (State s a) is a function from initial state s to final value a and final state s: (a,s). These are usually wrapped, but shown here unwrapped for simplicity.
Return leaves the state unchanged and sets the result:
 ie: (return 5) 1 > (5,1)
return :: a > State s a
return x s = (x,s)
Get leaves state unchanged and sets the result to the state:
 ie: get 1 > (1,1)
get :: State s s
get s = (s,s)
Put sets the result to () and sets the state:
 ie: (put 5) 1 > ((),5)
put :: s > State s ()
put x s = ((),x)
The helpers are simple variations of these primitives:
modify :: (s > s) > State s ()
modify f = do { x < get; put (f x) }
gets :: (s > a) > State s a
gets f = do { x < get; return (f x) }
EvalState and execState just select one of the two values returned by runState. EvalState returns the final result while execState returns the final state:
evalState :: State s a > s > a
evalState act = fst . runState act
execState :: State s a > s > s
execState act = snd . runState act
Combining two states is the trickiest bit in the whole scheme. To combine do { x < act1; act2 x } we need a function which takes an initial state, runs act1 to get an intermediate result and state, feeds the intermediate result to act2 and then runs that action with the intermediate state to get a final result and a final state:
(>>=) :: State s a > (a > State s b) > State s b
(act1 >>= fact2) s = runState act2 is
where (iv,is) = runState act1 s
act2 = fact2 iv
Complete and Concrete Example 1
Simple example that demonstrates the use of the standard Control.Monad.State monad. Its a simple string parsing algorithm.
module StateGame where
import Control.Monad.State
 Example use of State monad
 Passes a string of dictionary {a,b,c}
 Game is to produce a number from the string.
 By default the game is off, a C toggles the
 game on and off. A 'a' gives +1 and a b gives 1.
 E.g
 'ab' = 0
 'ca' = 1
 'cabca' = 0
 State = game is on or off & current score
 = (Bool, Int)
type GameValue = Int
type GameState = (Bool, Int)
playGame :: String > State GameState GameValue
playGame [] = do
(_, score) < get
return score
playGame (x:xs) = do
(on, score) < get
case x of
'a'  on > put (on, score + 1)
'b'  on > put (on, score  1)
'c' > put (not on, score)
_ > put (on, score)
playGame xs
startState = (False, 0)
main = print $ evalState (playGame "abcaaacbbcabbab") startState
Complete and Concrete Example 2
 a concrete and simple example of using the State monad
import Control.Monad.State
 non monadic version of a very simple state example
 the State is an integer.
 the value will always be the negative of of the state
type MyState = Int
valFromState :: MyState > Int
valFromState s = s
nextState :: MyState>MyState
nextState x = 1+x
type MyStateMonad = State MyState
 this is it, the State transformation. Add 1 to the state, return 1*the state as the computed value.
getNext :: MyStateMonad Int
getNext = state (\st > let st' = nextState(st) in (valFromState(st'),st') )
 advance the state three times.
inc3::MyStateMonad Int
inc3 = getNext >>= \x >
getNext >>= \y >
getNext >>= \z >
return z
 advance the state three times with do sugar
inc3Sugared::MyStateMonad Int
inc3Sugared = do x < getNext
y < getNext
z < getNext
return z
 advance the state three times without inspecting computed values
inc3DiscardedValues::MyStateMonad Int
inc3DiscardedValues = getNext >> getNext >> getNext
 advance the state three times without inspecting computed values with do sugar
inc3DiscardedValuesSugared::MyStateMonad Int
inc3DiscardedValuesSugared = do
getNext
getNext
getNext
 advance state 3 times, compute the square of the state
inc3AlternateResult::MyStateMonad Int
inc3AlternateResult = do getNext
getNext
getNext
s<get
return (s*s)
 advance state 3 times, ignoring computed value, and then once more
inc4::MyStateMonad Int
inc4 = do
inc3AlternateResult
getNext
main =
do
print (evalState inc3 0)  3
print (evalState inc3Sugared 0)  3
print (evalState inc3DiscardedValues 0)  3
print (evalState inc3DiscardedValuesSugared 0)  3
print (evalState inc3AlternateResult 0)  9
print (evalState inc4 0)  4