# 99 questions/Solutions/2

### From HaskellWiki

(*) Find the last but one element of a list.

myButLast :: [a] -> a myButLast = last . init myButLast' x = reverse x !! 1 myButLast'' [x,_] = x myButLast'' (_:xs) = myButLast'' xs myButLast''' (x:(_:[])) = x myButLast''' (_:xs) = myButLast''' xs myButLast'''' = head . tail . reverse lastbut1 :: Foldable f => f a -> a lastbut1 = fst . foldl (\(a,b) x -> (b,x)) (err1,err2) where err1 = error "lastbut1: Empty list" err2 = error "lastbut1: Singleton" lastbut1safe :: Foldable f => f a -> Maybe a lastbut1safe = fst . foldl (\(a,b) x -> (b,Just x)) (Nothing,Nothing) myButLast''''' [] = error "Empty list" myButLast''''' [x] = error "Too few elements" myButLast''''' (x:xs) = if length xs == 1 then x else myButLast''''' xs myButLast'''''' = head . reverse . init