If I choose four cards from a standard -card deck, with replacement, what is the probability that I will end up with one card from each suit, or four Aces?

Guest Apr 23, 2021

#1**-1 **

there are 4x3x2 ways to get one from each suit, which includes aces.

there are 4x4x4x4 ways in total, so (4x3x2)/(4x4x4x4)=$\boxed{\dfrac3{32}}$

SparklingWater2 Apr 23, 2021